Termination Proof Script
Consider the TRS R consisting of the rewrite rules
|
1: |
|
half(0) |
→ 0 |
2: |
|
half(s(0)) |
→ 0 |
3: |
|
half(s(s(x))) |
→ s(half(x)) |
4: |
|
bits(0) |
→ 0 |
5: |
|
bits(s(x)) |
→ s(bits(half(s(x)))) |
|
There are 3 dependency pairs:
|
6: |
|
HALF(s(s(x))) |
→ HALF(x) |
7: |
|
BITS(s(x)) |
→ BITS(half(s(x))) |
8: |
|
BITS(s(x)) |
→ HALF(s(x)) |
|
The approximated dependency graph contains 2 SCCs:
{6}
and {7}.
-
Consider the SCC {6}.
There are no usable rules.
By taking the AF π with
π(HALF) = 1 together with
the lexicographic path order with
empty precedence,
rule 6
is strictly decreasing.
-
Consider the SCC {7}.
The usable rules are {1-3}.
The constraints could not be solved.
Tyrolean Termination Tool (0.02 seconds)
--- May 4, 2006